Palindrome Number

 

  1. Clarify the problem:

    • The problem requires determining whether a given integer is a palindrome.
    • A palindrome number is a number that reads the same backward as forward.
    • We need to implement a function that takes an integer as input and returns a boolean indicating whether it is a palindrome.
  2. Analyze the problem:

    • Input: An integer.
    • Output: A boolean indicating whether the integer is a palindrome.
    • Constraints:
      • The input integer can be negative, but negative numbers are not considered palindromes.
  3. Design an algorithm:

    • We can convert the integer to a string and check if the string is a palindrome.
    • To check if a string is a palindrome, we can compare the characters from the beginning and the end of the string.
    • We will use two pointers, one starting from the beginning of the string and the other starting from the end.
    • We will compare the characters at the two pointers and move them towards the center until they meet or cross each other.
    • If all the characters match, the string is a palindrome. Otherwise, it is not.
  4. Explain your approach:

    • We will implement a function called isPalindrome that takes an integer as input.
    • We will convert the integer to a string using the built-in str() function.
    • We will initialize two pointers, left and right, pointing to the beginning and the end of the string, respectively.
    • We will compare the characters at the two pointers using string indexing.
    • If the characters match, we will move left one step forward and right one step backward.
    • We will continue this process until left is greater than or equal to right.
    • If all the characters match, we will return True indicating that the integer is a palindrome. Otherwise, we will return False.
  5. Write clean and readable code:

    python
  6. def isPalindrome(x): if x < 0: return False # Convert integer to string s = str(x) left = 0 right = len(s) - 1 while left < right: if s[left] != s[right]: return False left += 1 right -= 1 return True
  7. Test your code:

    python
  8. # Test case 1 x = 121 # The number 121 is a palindrome. assert isPalindrome(x) == True # Test case 2 x = -121 # Negative numbers are not palindromes. assert isPalindrome(x) == False # Test case 3 x = 10 # The number 10 is not a palindrome. assert isPalindrome(x) == False # Test case 4 x = 12321 # The number 12321 is a palindrome. assert isPalindrome(x) == True
  9. Optimize if necessary:

    • The provided solution already has a simple and efficient algorithm for determining whether an integer is a palindrome.
    • There is no further optimization possible for this problem.
  10. Handle error cases:

    • The given code assumes that t
Next Post Previous Post