Palindrome Number
Clarify the problem:
- The problem requires determining whether a given integer is a palindrome.
- A palindrome number is a number that reads the same backward as forward.
- We need to implement a function that takes an integer as input and returns a boolean indicating whether it is a palindrome.
Analyze the problem:
- Input: An integer.
- Output: A boolean indicating whether the integer is a palindrome.
- Constraints:
- The input integer can be negative, but negative numbers are not considered palindromes.
Design an algorithm:
- We can convert the integer to a string and check if the string is a palindrome.
- To check if a string is a palindrome, we can compare the characters from the beginning and the end of the string.
- We will use two pointers, one starting from the beginning of the string and the other starting from the end.
- We will compare the characters at the two pointers and move them towards the center until they meet or cross each other.
- If all the characters match, the string is a palindrome. Otherwise, it is not.
Explain your approach:
- We will implement a function called
isPalindrome
that takes an integer as input. - We will convert the integer to a string using the built-in
str()
function. - We will initialize two pointers,
left
andright
, pointing to the beginning and the end of the string, respectively. - We will compare the characters at the two pointers using string indexing.
- If the characters match, we will move
left
one step forward andright
one step backward. - We will continue this process until
left
is greater than or equal toright
. - If all the characters match, we will return
True
indicating that the integer is a palindrome. Otherwise, we will returnFalse
.
- We will implement a function called
Write clean and readable code:
pythondef isPalindrome(x): if x < 0: return False # Convert integer to string s = str(x) left = 0 right = len(s) - 1 while left < right: if s[left] != s[right]: return False left += 1 right -= 1 return True
Test your code:
python# Test case 1 x = 121 # The number 121 is a palindrome. assert isPalindrome(x) == True # Test case 2 x = -121 # Negative numbers are not palindromes. assert isPalindrome(x) == False # Test case 3 x = 10 # The number 10 is not a palindrome. assert isPalindrome(x) == False # Test case 4 x = 12321 # The number 12321 is a palindrome. assert isPalindrome(x) == True
Optimize if necessary:
- The provided solution already has a simple and efficient algorithm for determining whether an integer is a palindrome.
- There is no further optimization possible for this problem.
Handle error cases:
- The given code assumes that t